Solución - Tiger Algebra Solver

$${\left(9D8\right)}_{16}$$

Pasos: $$9·{16}^2$$
+ $$13·{16}^1$$
+ $$8·{16}^0$$ = $$2.520$$.

$$9\cdot {16}^2+13\cdot {16}^1+8\cdot {16}^0$$

Pasos: $$9·{16}^2$$
+ $$13·{16}^1$$
+ $$8·{16}^0$$ = $$2.520$$.

$$2520$$

Pasos: $$9·{16}^2$$
+ $$13·{16}^1$$
+ $$8·{16}^0$$ = $$2,520$$.

$$2520\left(base10\right)$$

$${2.520}_{10}={2.520}_{10}$$.

$$\frac{2520}{10}$$

$${2.520}_{10}={2.520}_{10}$$.

$$2520=10\cdot 252+0$$

$${2.520}_{10}={2.520}_{10}$$.

$$252=10\cdot 25+2$$

$${2.520}_{10}={2.520}_{10}$$.

$$25=10\cdot 2+5$$

$${2.520}_{10}={2.520}_{10}$$.

$$2=10\cdot 0+2$$

$${2.520}_{10}={2.520}_{10}$$.

$$2520$$

$${2.520}_{10}={2.520}_{10}$$.

$${\left(2520\right)}_{10}$$

$$2,{520}_{10}=2,{520}_{10}$$.