Solución - Tiger Algebra Solver

$${\left(9D4\right)}_{16}$$

Pasos: $$9·{16}^2$$
+ $$13·{16}^1$$
+ $$4·{16}^0$$ = $$2.516$$.

$$9\cdot {16}^2+13\cdot {16}^1+4\cdot {16}^0$$

Pasos: $$9·{16}^2$$
+ $$13·{16}^1$$
+ $$4·{16}^0$$ = $$2.516$$.

$$2516$$

Pasos: $$9·{16}^2$$
+ $$13·{16}^1$$
+ $$4·{16}^0$$ = $$2,516$$.

$$2516\left(base10\right)$$

$${2.516}_{10}={2.516}_{10}$$.

$$\frac{2516}{10}$$

$${2.516}_{10}={2.516}_{10}$$.

$$2516=10\cdot 251+6$$

$${2.516}_{10}={2.516}_{10}$$.

$$251=10\cdot 25+1$$

$${2.516}_{10}={2.516}_{10}$$.

$$25=10\cdot 2+5$$

$${2.516}_{10}={2.516}_{10}$$.

$$2=10\cdot 0+2$$

$${2.516}_{10}={2.516}_{10}$$.

$$2516$$

$${2.516}_{10}={2.516}_{10}$$.

$${\left(2516\right)}_{10}$$

$$2,{516}_{10}=2,{516}_{10}$$.