Solución - Tiger Algebra Solver

$${\left(8C9\right)}_{16}$$

Pasos: $$8·{16}^2$$
+ $$12·{16}^1$$
+ $$9·{16}^0$$ = $$2.249$$.

$$8\cdot {16}^2+12\cdot {16}^1+9\cdot {16}^0$$

Pasos: $$8·{16}^2$$
+ $$12·{16}^1$$
+ $$9·{16}^0$$ = $$2.249$$.

$$2249$$

Pasos: $$8·{16}^2$$
+ $$12·{16}^1$$
+ $$9·{16}^0$$ = $$2,249$$.

$$2249\left(base10\right)$$

$${2.249}_{10}={2.249}_{10}$$.

$$\frac{2249}{10}$$

$${2.249}_{10}={2.249}_{10}$$.

$$2249=10\cdot 224+9$$

$${2.249}_{10}={2.249}_{10}$$.

$$224=10\cdot 22+4$$

$${2.249}_{10}={2.249}_{10}$$.

$$22=10\cdot 2+2$$

$${2.249}_{10}={2.249}_{10}$$.

$$2=10\cdot 0+2$$

$${2.249}_{10}={2.249}_{10}$$.

$$2249$$

$${2.249}_{10}={2.249}_{10}$$.

$${\left(2249\right)}_{10}$$

$$2,{249}_{10}=2,{249}_{10}$$.