Solución - Tiger Algebra Solver

$${\left(8A6\right)}_{16}$$

Pasos: $$8·{16}^2$$
+ $$10·{16}^1$$
+ $$6·{16}^0$$ = $$2.214$$.

$$8\cdot {16}^2+10\cdot {16}^1+6\cdot {16}^0$$

Pasos: $$8·{16}^2$$
+ $$10·{16}^1$$
+ $$6·{16}^0$$ = $$2.214$$.

$$2214$$

Pasos: $$8·{16}^2$$
+ $$10·{16}^1$$
+ $$6·{16}^0$$ = $$2,214$$.

$$2214\left(base10\right)$$

$${2.214}_{10}={2.214}_{10}$$.

$$\frac{2214}{10}$$

$${2.214}_{10}={2.214}_{10}$$.

$$2214=10\cdot 221+4$$

$${2.214}_{10}={2.214}_{10}$$.

$$221=10\cdot 22+1$$

$${2.214}_{10}={2.214}_{10}$$.

$$22=10\cdot 2+2$$

$${2.214}_{10}={2.214}_{10}$$.

$$2=10\cdot 0+2$$

$${2.214}_{10}={2.214}_{10}$$.

$$2214$$

$${2.214}_{10}={2.214}_{10}$$.

$${\left(2214\right)}_{10}$$

$$2,{214}_{10}=2,{214}_{10}$$.