Solución - Tiger Algebra Solver

$${\left(8A5\right)}_{16}$$

Pasos: $$8·{16}^2$$
+ $$10·{16}^1$$
+ $$5·{16}^0$$ = $$2.213$$.

$$8\cdot {16}^2+10\cdot {16}^1+5\cdot {16}^0$$

Pasos: $$8·{16}^2$$
+ $$10·{16}^1$$
+ $$5·{16}^0$$ = $$2.213$$.

$$2213$$

Pasos: $$8·{16}^2$$
+ $$10·{16}^1$$
+ $$5·{16}^0$$ = $$2,213$$.

$$2213\left(base10\right)$$

$${2.213}_{10}={2.213}_{10}$$.

$$\frac{2213}{10}$$

$${2.213}_{10}={2.213}_{10}$$.

$$2213=10\cdot 221+3$$

$${2.213}_{10}={2.213}_{10}$$.

$$221=10\cdot 22+1$$

$${2.213}_{10}={2.213}_{10}$$.

$$22=10\cdot 2+2$$

$${2.213}_{10}={2.213}_{10}$$.

$$2=10\cdot 0+2$$

$${2.213}_{10}={2.213}_{10}$$.

$$2213$$

$${2.213}_{10}={2.213}_{10}$$.

$${\left(2213\right)}_{10}$$

$$2,{213}_{10}=2,{213}_{10}$$.