Solución - Tiger Algebra Solver

$${\left(7D6\right)}_{16}$$

Pasos: $$7·{16}^2$$
+ $$13·{16}^1$$
+ $$6·{16}^0$$ = $$2.006$$.

$$7\cdot {16}^2+13\cdot {16}^1+6\cdot {16}^0$$

Pasos: $$7·{16}^2$$
+ $$13·{16}^1$$
+ $$6·{16}^0$$ = $$2.006$$.

$$2006$$

Pasos: $$7·{16}^2$$
+ $$13·{16}^1$$
+ $$6·{16}^0$$ = $$2,006$$.

$$2006\left(base10\right)$$

$${2.006}_{10}={2.006}_{10}$$.

$$\frac{2006}{10}$$

$${2.006}_{10}={2.006}_{10}$$.

$$2006=10\cdot 200+6$$

$${2.006}_{10}={2.006}_{10}$$.

$$200=10\cdot 20+0$$

$${2.006}_{10}={2.006}_{10}$$.

$$20=10\cdot 2+0$$

$${2.006}_{10}={2.006}_{10}$$.

$$2=10\cdot 0+2$$

$${2.006}_{10}={2.006}_{10}$$.

$$2006$$

$${2.006}_{10}={2.006}_{10}$$.

$${\left(2006\right)}_{10}$$

$$2,{006}_{10}=2,{006}_{10}$$.