Solución - Tiger Algebra Solver

$${\left(7D1\right)}_{16}$$

Pasos: $$7·{16}^2$$
+ $$13·{16}^1$$
+ $$1·{16}^0$$ = $$2.001$$.

$$7\cdot {16}^2+13\cdot {16}^1+1\cdot {16}^0$$

Pasos: $$7·{16}^2$$
+ $$13·{16}^1$$
+ $$1·{16}^0$$ = $$2.001$$.

$$2001$$

Pasos: $$7·{16}^2$$
+ $$13·{16}^1$$
+ $$1·{16}^0$$ = $$2,001$$.

$$2001\left(base10\right)$$

$${2.001}_{10}={2.001}_{10}$$.

$$\frac{2001}{10}$$

$${2.001}_{10}={2.001}_{10}$$.

$$2001=10\cdot 200+1$$

$${2.001}_{10}={2.001}_{10}$$.

$$200=10\cdot 20+0$$

$${2.001}_{10}={2.001}_{10}$$.

$$20=10\cdot 2+0$$

$${2.001}_{10}={2.001}_{10}$$.

$$2=10\cdot 0+2$$

$${2.001}_{10}={2.001}_{10}$$.

$$2001$$

$${2.001}_{10}={2.001}_{10}$$.

$${\left(2001\right)}_{10}$$

$$2,{001}_{10}=2,{001}_{10}$$.