Solución - Tiger Algebra Solver

$${\left(7B0\right)}_{16}$$

Pasos: $$7·{16}^2$$
+ $$11·{16}^1$$
+ $$0·{16}^0$$ = $$1.968$$.

$$7\cdot {16}^2+11\cdot {16}^1+0\cdot {16}^0$$

Pasos: $$7·{16}^2$$
+ $$11·{16}^1$$
+ $$0·{16}^0$$ = $$1.968$$.

$$1968$$

Pasos: $$7·{16}^2$$
+ $$11·{16}^1$$
+ $$0·{16}^0$$ = $$1,968$$.

$$1968\left(base10\right)$$

$${1.968}_{10}={1.968}_{10}$$.

$$\frac{1968}{10}$$

$${1.968}_{10}={1.968}_{10}$$.

$$1968=10\cdot 196+8$$

$${1.968}_{10}={1.968}_{10}$$.

$$196=10\cdot 19+6$$

$${1.968}_{10}={1.968}_{10}$$.

$$19=10\cdot 1+9$$

$${1.968}_{10}={1.968}_{10}$$.

$$1=10\cdot 0+1$$

$${1.968}_{10}={1.968}_{10}$$.

$$1968$$

$${1.968}_{10}={1.968}_{10}$$.

$${\left(1968\right)}_{10}$$

$$1,{968}_{10}=1,{968}_{10}$$.