Solución - Tiger Algebra Solver

$${\left(7A8\right)}_{16}$$

Pasos: $$7·{16}^2$$
+ $$10·{16}^1$$
+ $$8·{16}^0$$ = $$1.960$$.

$$7\cdot {16}^2+10\cdot {16}^1+8\cdot {16}^0$$

Pasos: $$7·{16}^2$$
+ $$10·{16}^1$$
+ $$8·{16}^0$$ = $$1.960$$.

$$1960$$

Pasos: $$7·{16}^2$$
+ $$10·{16}^1$$
+ $$8·{16}^0$$ = $$1,960$$.

$$1960\left(base10\right)$$

$${1.960}_{10}={1.960}_{10}$$.

$$\frac{1960}{10}$$

$${1.960}_{10}={1.960}_{10}$$.

$$1960=10\cdot 196+0$$

$${1.960}_{10}={1.960}_{10}$$.

$$196=10\cdot 19+6$$

$${1.960}_{10}={1.960}_{10}$$.

$$19=10\cdot 1+9$$

$${1.960}_{10}={1.960}_{10}$$.

$$1=10\cdot 0+1$$

$${1.960}_{10}={1.960}_{10}$$.

$$1960$$

$${1.960}_{10}={1.960}_{10}$$.

$${\left(1960\right)}_{10}$$

$$1,{960}_{10}=1,{960}_{10}$$.