Solución - Tiger Algebra Solver

$${\left(5D9\right)}_{16}$$

Pasos: $$5·{16}^2$$
+ $$13·{16}^1$$
+ $$9·{16}^0$$ = $$1.497$$.

$$5\cdot {16}^2+13\cdot {16}^1+9\cdot {16}^0$$

Pasos: $$5·{16}^2$$
+ $$13·{16}^1$$
+ $$9·{16}^0$$ = $$1.497$$.

$$1497$$

Pasos: $$5·{16}^2$$
+ $$13·{16}^1$$
+ $$9·{16}^0$$ = $$1,497$$.

$$1497\left(base10\right)$$

$${1.497}_{10}={1.497}_{10}$$.

$$\frac{1497}{10}$$

$${1.497}_{10}={1.497}_{10}$$.

$$1497=10\cdot 149+7$$

$${1.497}_{10}={1.497}_{10}$$.

$$149=10\cdot 14+9$$

$${1.497}_{10}={1.497}_{10}$$.

$$14=10\cdot 1+4$$

$${1.497}_{10}={1.497}_{10}$$.

$$1=10\cdot 0+1$$

$${1.497}_{10}={1.497}_{10}$$.

$$1497$$

$${1.497}_{10}={1.497}_{10}$$.

$${\left(1497\right)}_{10}$$

$$1,{497}_{10}=1,{497}_{10}$$.