Solución - Tiger Algebra Solver

$${\left(5C9\right)}_{16}$$

Pasos: $$5·{16}^2$$
+ $$12·{16}^1$$
+ $$9·{16}^0$$ = $$1.481$$.

$$5\cdot {16}^2+12\cdot {16}^1+9\cdot {16}^0$$

Pasos: $$5·{16}^2$$
+ $$12·{16}^1$$
+ $$9·{16}^0$$ = $$1.481$$.

$$1481$$

Pasos: $$5·{16}^2$$
+ $$12·{16}^1$$
+ $$9·{16}^0$$ = $$1,481$$.

$$1481\left(base10\right)$$

$${1.481}_{10}={1.481}_{10}$$.

$$\frac{1481}{10}$$

$${1.481}_{10}={1.481}_{10}$$.

$$1481=10\cdot 148+1$$

$${1.481}_{10}={1.481}_{10}$$.

$$148=10\cdot 14+8$$

$${1.481}_{10}={1.481}_{10}$$.

$$14=10\cdot 1+4$$

$${1.481}_{10}={1.481}_{10}$$.

$$1=10\cdot 0+1$$

$${1.481}_{10}={1.481}_{10}$$.

$$1481$$

$${1.481}_{10}={1.481}_{10}$$.

$${\left(1481\right)}_{10}$$

$$1,{481}_{10}=1,{481}_{10}$$.