Solución - Tiger Algebra Solver

$${\left(5C1\right)}_{16}$$

Pasos: $$5·{16}^2$$
+ $$12·{16}^1$$
+ $$1·{16}^0$$ = $$1.473$$.

$$5\cdot {16}^2+12\cdot {16}^1+1\cdot {16}^0$$

Pasos: $$5·{16}^2$$
+ $$12·{16}^1$$
+ $$1·{16}^0$$ = $$1.473$$.

$$1473$$

Pasos: $$5·{16}^2$$
+ $$12·{16}^1$$
+ $$1·{16}^0$$ = $$1,473$$.

$$1473\left(base10\right)$$

$${1.473}_{10}={1.473}_{10}$$.

$$\frac{1473}{10}$$

$${1.473}_{10}={1.473}_{10}$$.

$$1473=10\cdot 147+3$$

$${1.473}_{10}={1.473}_{10}$$.

$$147=10\cdot 14+7$$

$${1.473}_{10}={1.473}_{10}$$.

$$14=10\cdot 1+4$$

$${1.473}_{10}={1.473}_{10}$$.

$$1=10\cdot 0+1$$

$${1.473}_{10}={1.473}_{10}$$.

$$1473$$

$${1.473}_{10}={1.473}_{10}$$.

$${\left(1473\right)}_{10}$$

$$1,{473}_{10}=1,{473}_{10}$$.