Solución - Tiger Algebra Solver

$${\left(5B9\right)}_{16}$$

Pasos: $$5·{16}^2$$
+ $$11·{16}^1$$
+ $$9·{16}^0$$ = $$1.465$$.

$$5\cdot {16}^2+11\cdot {16}^1+9\cdot {16}^0$$

Pasos: $$5·{16}^2$$
+ $$11·{16}^1$$
+ $$9·{16}^0$$ = $$1.465$$.

$$1465$$

Pasos: $$5·{16}^2$$
+ $$11·{16}^1$$
+ $$9·{16}^0$$ = $$1,465$$.

$$1465\left(base10\right)$$

$${1.465}_{10}={1.465}_{10}$$.

$$\frac{1465}{10}$$

$${1.465}_{10}={1.465}_{10}$$.

$$1465=10\cdot 146+5$$

$${1.465}_{10}={1.465}_{10}$$.

$$146=10\cdot 14+6$$

$${1.465}_{10}={1.465}_{10}$$.

$$14=10\cdot 1+4$$

$${1.465}_{10}={1.465}_{10}$$.

$$1=10\cdot 0+1$$

$${1.465}_{10}={1.465}_{10}$$.

$$1465$$

$${1.465}_{10}={1.465}_{10}$$.

$${\left(1465\right)}_{10}$$

$$1,{465}_{10}=1,{465}_{10}$$.