Solución - Tiger Algebra Solver

$${\left(5B5\right)}_{16}$$

Pasos: $$5·{16}^2$$
+ $$11·{16}^1$$
+ $$5·{16}^0$$ = $$1.461$$.

$$5\cdot {16}^2+11\cdot {16}^1+5\cdot {16}^0$$

Pasos: $$5·{16}^2$$
+ $$11·{16}^1$$
+ $$5·{16}^0$$ = $$1.461$$.

$$1461$$

Pasos: $$5·{16}^2$$
+ $$11·{16}^1$$
+ $$5·{16}^0$$ = $$1,461$$.

$$1461\left(base10\right)$$

$${1.461}_{10}={1.461}_{10}$$.

$$\frac{1461}{10}$$

$${1.461}_{10}={1.461}_{10}$$.

$$1461=10\cdot 146+1$$

$${1.461}_{10}={1.461}_{10}$$.

$$146=10\cdot 14+6$$

$${1.461}_{10}={1.461}_{10}$$.

$$14=10\cdot 1+4$$

$${1.461}_{10}={1.461}_{10}$$.

$$1=10\cdot 0+1$$

$${1.461}_{10}={1.461}_{10}$$.

$$1461$$

$${1.461}_{10}={1.461}_{10}$$.

$${\left(1461\right)}_{10}$$

$$1,{461}_{10}=1,{461}_{10}$$.