Solución - Tiger Algebra Solver

$${\left(5A4\right)}_{16}$$

Pasos: $$5·{16}^2$$
+ $$10·{16}^1$$
+ $$4·{16}^0$$ = $$1.444$$.

$$5\cdot {16}^2+10\cdot {16}^1+4\cdot {16}^0$$

Pasos: $$5·{16}^2$$
+ $$10·{16}^1$$
+ $$4·{16}^0$$ = $$1.444$$.

$$1444$$

Pasos: $$5·{16}^2$$
+ $$10·{16}^1$$
+ $$4·{16}^0$$ = $$1,444$$.

$$1444\left(base10\right)$$

$${1.444}_{10}={1.444}_{10}$$.

$$\frac{1444}{10}$$

$${1.444}_{10}={1.444}_{10}$$.

$$1444=10\cdot 144+4$$

$${1.444}_{10}={1.444}_{10}$$.

$$144=10\cdot 14+4$$

$${1.444}_{10}={1.444}_{10}$$.

$$14=10\cdot 1+4$$

$${1.444}_{10}={1.444}_{10}$$.

$$1=10\cdot 0+1$$

$${1.444}_{10}={1.444}_{10}$$.

$$1444$$

$${1.444}_{10}={1.444}_{10}$$.

$${\left(1444\right)}_{10}$$

$$1,{444}_{10}=1,{444}_{10}$$.