Solución - Tiger Algebra Solver

$${\left(4F8\right)}_{16}$$

Pasos: $$4·{16}^2$$
+ $$15·{16}^1$$
+ $$8·{16}^0$$ = $$1.272$$.

$$4\cdot {16}^2+15\cdot {16}^1+8\cdot {16}^0$$

Pasos: $$4·{16}^2$$
+ $$15·{16}^1$$
+ $$8·{16}^0$$ = $$1.272$$.

$$1272$$

Pasos: $$4·{16}^2$$
+ $$15·{16}^1$$
+ $$8·{16}^0$$ = $$1,272$$.

$$1272\left(base10\right)$$

$${1.272}_{10}={1.272}_{10}$$.

$$\frac{1272}{10}$$

$${1.272}_{10}={1.272}_{10}$$.

$$1272=10\cdot 127+2$$

$${1.272}_{10}={1.272}_{10}$$.

$$127=10\cdot 12+7$$

$${1.272}_{10}={1.272}_{10}$$.

$$12=10\cdot 1+2$$

$${1.272}_{10}={1.272}_{10}$$.

$$1=10\cdot 0+1$$

$${1.272}_{10}={1.272}_{10}$$.

$$1272$$

$${1.272}_{10}={1.272}_{10}$$.

$${\left(1272\right)}_{10}$$

$$1,{272}_{10}=1,{272}_{10}$$.