Solución - Tiger Algebra Solver

$${\left(4F2\right)}_{16}$$

Pasos: $$4·{16}^2$$
+ $$15·{16}^1$$
+ $$2·{16}^0$$ = $$1.266$$.

$$4\cdot {16}^2+15\cdot {16}^1+2\cdot {16}^0$$

Pasos: $$4·{16}^2$$
+ $$15·{16}^1$$
+ $$2·{16}^0$$ = $$1.266$$.

$$1266$$

Pasos: $$4·{16}^2$$
+ $$15·{16}^1$$
+ $$2·{16}^0$$ = $$1,266$$.

$$1266\left(base10\right)$$

$${1.266}_{10}={1.266}_{10}$$.

$$\frac{1266}{10}$$

$${1.266}_{10}={1.266}_{10}$$.

$$1266=10\cdot 126+6$$

$${1.266}_{10}={1.266}_{10}$$.

$$126=10\cdot 12+6$$

$${1.266}_{10}={1.266}_{10}$$.

$$12=10\cdot 1+2$$

$${1.266}_{10}={1.266}_{10}$$.

$$1=10\cdot 0+1$$

$${1.266}_{10}={1.266}_{10}$$.

$$1266$$

$${1.266}_{10}={1.266}_{10}$$.

$${\left(1266\right)}_{10}$$

$$1,{266}_{10}=1,{266}_{10}$$.