Solución - Tiger Algebra Solver

$${\left(3E9\right)}_{16}$$

Pasos: $$3·{16}^2$$
+ $$14·{16}^1$$
+ $$9·{16}^0$$ = $$1.001$$.

$$3\cdot {16}^2+14\cdot {16}^1+9\cdot {16}^0$$

Pasos: $$3·{16}^2$$
+ $$14·{16}^1$$
+ $$9·{16}^0$$ = $$1.001$$.

$$1001$$

Pasos: $$3·{16}^2$$
+ $$14·{16}^1$$
+ $$9·{16}^0$$ = $$1,001$$.

$$1001\left(base10\right)$$

$${1.001}_{10}={1.001}_{10}$$.

$$\frac{1001}{10}$$

$${1.001}_{10}={1.001}_{10}$$.

$$1001=10\cdot 100+1$$

$${1.001}_{10}={1.001}_{10}$$.

$$100=10\cdot 10+0$$

$${1.001}_{10}={1.001}_{10}$$.

$$10=10\cdot 1+0$$

$${1.001}_{10}={1.001}_{10}$$.

$$1=10\cdot 0+1$$

$${1.001}_{10}={1.001}_{10}$$.

$$1001$$

$${1.001}_{10}={1.001}_{10}$$.

$${\left(1001\right)}_{10}$$

$$1,{001}_{10}=1,{001}_{10}$$.