Solución - Tiger Algebra Solver

$${\left(3C7\right)}_{16}$$

Pasos: $$3·{16}^2$$
+ $$12·{16}^1$$
+ $$7·{16}^0$$ = $$967$$.

$$3\cdot {16}^2+12\cdot {16}^1+7\cdot {16}^0$$

Pasos: $$3·{16}^2$$
+ $$12·{16}^1$$
+ $$7·{16}^0$$ = $$967$$.

$$967$$

Pasos: $$3·{16}^2$$
+ $$12·{16}^1$$
+ $$7·{16}^0$$ = $$967$$.

$$967\left(base10\right)$$

$${967}_{10}={967}_{10}$$.

$$\frac{967}{10}$$

$${967}_{10}={967}_{10}$$.

$$967=10\cdot 96+7$$

$${967}_{10}={967}_{10}$$.

$$96=10\cdot 9+6$$

$${967}_{10}={967}_{10}$$.

$$9=10\cdot 0+9$$

$${967}_{10}={967}_{10}$$.

$$967$$

$${967}_{10}={967}_{10}$$.

$${\left(967\right)}_{10}$$

$${967}_{10}={967}_{10}$$.