Solución - Tiger Algebra Solver

$${\left(3C0\right)}_{16}$$

Pasos: $$3·{16}^2$$
+ $$12·{16}^1$$
+ $$0·{16}^0$$ = $$960$$.

$$3\cdot {16}^2+12\cdot {16}^1+0\cdot {16}^0$$

Pasos: $$3·{16}^2$$
+ $$12·{16}^1$$
+ $$0·{16}^0$$ = $$960$$.

$$960$$

Pasos: $$3·{16}^2$$
+ $$12·{16}^1$$
+ $$0·{16}^0$$ = $$960$$.

$$960\left(base10\right)$$

$${960}_{10}={960}_{10}$$.

$$\frac{960}{10}$$

$${960}_{10}={960}_{10}$$.

$$960=10\cdot 96+0$$

$${960}_{10}={960}_{10}$$.

$$96=10\cdot 9+6$$

$${960}_{10}={960}_{10}$$.

$$9=10\cdot 0+9$$

$${960}_{10}={960}_{10}$$.

$$960$$

$${960}_{10}={960}_{10}$$.

$${\left(960\right)}_{10}$$

$${960}_{10}={960}_{10}$$.