Solución - Tiger Algebra Solver

$${\left(2E9\right)}_{16}$$

Pasos: $$2·{16}^2$$
+ $$14·{16}^1$$
+ $$9·{16}^0$$ = $$745$$.

$$2\cdot {16}^2+14\cdot {16}^1+9\cdot {16}^0$$

Pasos: $$2·{16}^2$$
+ $$14·{16}^1$$
+ $$9·{16}^0$$ = $$745$$.

$$745$$

Pasos: $$2·{16}^2$$
+ $$14·{16}^1$$
+ $$9·{16}^0$$ = $$745$$.

$$745\left(base10\right)$$

$${745}_{10}={745}_{10}$$.

$$\frac{745}{10}$$

$${745}_{10}={745}_{10}$$.

$$745=10\cdot 74+5$$

$${745}_{10}={745}_{10}$$.

$$74=10\cdot 7+4$$

$${745}_{10}={745}_{10}$$.

$$7=10\cdot 0+7$$

$${745}_{10}={745}_{10}$$.

$$745$$

$${745}_{10}={745}_{10}$$.

$${\left(745\right)}_{10}$$

$${745}_{10}={745}_{10}$$.