Solución - Tiger Algebra Solver

$${\left(2A8\right)}_{16}$$

Pasos: $$2·{16}^2$$
+ $$10·{16}^1$$
+ $$8·{16}^0$$ = $$680$$.

$$2\cdot {16}^2+10\cdot {16}^1+8\cdot {16}^0$$

Pasos: $$2·{16}^2$$
+ $$10·{16}^1$$
+ $$8·{16}^0$$ = $$680$$.

$$680$$

Pasos: $$2·{16}^2$$
+ $$10·{16}^1$$
+ $$8·{16}^0$$ = $$680$$.

$$680\left(base10\right)$$

$${680}_{10}={680}_{10}$$.

$$\frac{680}{10}$$

$${680}_{10}={680}_{10}$$.

$$680=10\cdot 68+0$$

$${680}_{10}={680}_{10}$$.

$$68=10\cdot 6+8$$

$${680}_{10}={680}_{10}$$.

$$6=10\cdot 0+6$$

$${680}_{10}={680}_{10}$$.

$$680$$

$${680}_{10}={680}_{10}$$.

$${\left(680\right)}_{10}$$

$${680}_{10}={680}_{10}$$.