Solución - Tiger Algebra Solver

$${\left(2A0\right)}_{16}$$

Pasos: $$2·{16}^2$$
+ $$10·{16}^1$$
+ $$0·{16}^0$$ = $$672$$.

$$2\cdot {16}^2+10\cdot {16}^1+0\cdot {16}^0$$

Pasos: $$2·{16}^2$$
+ $$10·{16}^1$$
+ $$0·{16}^0$$ = $$672$$.

$$672$$

Pasos: $$2·{16}^2$$
+ $$10·{16}^1$$
+ $$0·{16}^0$$ = $$672$$.

$$672\left(base10\right)$$

$${672}_{10}={672}_{10}$$.

$$\frac{672}{10}$$

$${672}_{10}={672}_{10}$$.

$$672=10\cdot 67+2$$

$${672}_{10}={672}_{10}$$.

$$67=10\cdot 6+7$$

$${672}_{10}={672}_{10}$$.

$$6=10\cdot 0+6$$

$${672}_{10}={672}_{10}$$.

$$672$$

$${672}_{10}={672}_{10}$$.

$${\left(672\right)}_{10}$$

$${672}_{10}={672}_{10}$$.