Solución - Tiger Algebra Solver

$${\left(1D0\right)}_{16}$$

Pasos: $$1·{16}^2$$
+ $$13·{16}^1$$
+ $$0·{16}^0$$ = $$464$$.

$$1\cdot {16}^2+13\cdot {16}^1+0\cdot {16}^0$$

Pasos: $$1·{16}^2$$
+ $$13·{16}^1$$
+ $$0·{16}^0$$ = $$464$$.

$$464$$

Pasos: $$1·{16}^2$$
+ $$13·{16}^1$$
+ $$0·{16}^0$$ = $$464$$.

$$464\left(base10\right)$$

$${464}_{10}={464}_{10}$$.

$$\frac{464}{10}$$

$${464}_{10}={464}_{10}$$.

$$464=10\cdot 46+4$$

$${464}_{10}={464}_{10}$$.

$$46=10\cdot 4+6$$

$${464}_{10}={464}_{10}$$.

$$4=10\cdot 0+4$$

$${464}_{10}={464}_{10}$$.

$$464$$

$${464}_{10}={464}_{10}$$.

$${\left(464\right)}_{10}$$

$${464}_{10}={464}_{10}$$.