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Solution - Solving quadratic inequalities using the quadratic formula

Solution: x<1.352orx>10.352
x<-1.352 or x>10.352
Interval notation: x(,1.352)(10.352,)
x∈(-∞,-1.352)⋃(10.352,∞)

Step-by-step explanation

1. Determine the quadratic inequality's coefficients a, b and c

The coefficients of our inequality, x29x14>0, are:

a = 1

b = -9

c = -14

2. Plug these coefficients into the quadratic formula

To find the roots of a quadratic equation, plug its coefficients (a, b and c ) into the quadratic formula:

x=(-b±sqrt(b2-4ac))/(2a)

a=1
b=9
c=14

x=(-1*-9±sqrt(-92-4*1*-14))/(2*1)

Simplify the exponents and square roots

x=(-1*-9±sqrt(81-4*1*-14))/(2*1)

Perform any multiplication or division, from left to right:

x=(-1*-9±sqrt(81-4*-14))/(2*1)

x=(-1*-9±sqrt(81--56))/(2*1)

Calculate any addition or subtraction, from left to right.

x=(-1*-9±sqrt(81+56))/(2*1)

x=(-1*-9±sqrt(137))/(2*1)

Perform any multiplication or division, from left to right:

x=(-1*-9±sqrt(137))/(2)

Perform any multiplication or division, from left to right:

x=(9±sqrt(137))/2

to get the result:

x=(9±sqrt(137))/2

3. Simplify square root (137)

Simplify 137 by finding its prime factors:

The prime factorization of 137 is 137

Write the prime factors:

137=137

137=137

4. Solve the equation for x

x=(9±sqrt(137))/2

The ± means two roots are possible.

Separate the equations:
x1=(9+sqrt(137))/2 and x2=(9-sqrt(137))/2

x1=(9+sqrt(137))/2

Remove the parentheses

x1=(9+sqrt(137))/2

x1=(9+11.705)/2

Calculate any addition or subtraction, from left to right.

x1=(9+11.705)/2

x1=(20.705)/2

Perform any multiplication or division, from left to right:

x1=20.7052

x1=10.352

x2=(9-sqrt(137))/2

x2=(9-11.705)/2

Calculate any addition or subtraction, from left to right.

x2=(9-11.705)/2

x2=(-2.705)/2

Perform any multiplication or division, from left to right:

x2=2.7052

x2=1.352

5. Find the intervals

To find the intervals of a quadratic inequality, we start by finding its parabola.

The roots of the parabola (where it meets the x-axis) are: -1.352, 10.352.

Since the a coefficient is positive (a=1), this is a "positive" quadratic inequality and the parabola points upward, like a smile!

If the inequality sign is ≤ or ≥ , then the intervals include the roots and we use a solid line. If the inequality sign is < or > the intervals do not include the roots and we use a dotted line.

6. Choose the correct interval (solution)

Since x29x14>0 has a > inequality sign, we look for the parabola intervals that are above the x-axis.

Solution:

Interval notation:

Why learn this

Whereas quadratic equations express the paths of arcs and the points along them, quadratic inequalities express the areas within and outside of these arcs and the ranges they cover. In other words, if quadratic equations tell us where the boundary is, then quadratic inequalities help us understand what we should focus on relative to that boundary. More practically, quadratic inequalities are used to create complex algorithms that fuel powerful software and to track how changes, such as prices at the grocery store, happen over time.

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