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Solution - Solving quadratic inequalities using the quadratic formula

Solution: m<0.656orm>1.906
m<-0.656 or m>1.906
Interval notation: m(,0.656)(1.906,)
m∈(-∞,-0.656)⋃(1.906,∞)

Step-by-step explanation

1. Determine the quadratic inequality's coefficients a, b and c

The coefficients of our inequality, 4m25m5>0, are:

a = 4

b = -5

c = -5

2. Plug these coefficients into the quadratic formula

To find the roots of a quadratic equation, plug its coefficients (a, b and c ) into the quadratic formula:

m=(-b±sqrt(b2-4ac))/(2a)

a=4
b=5
c=5

m=(-1*-5±sqrt(-52-4*4*-5))/(2*4)

Simplify the exponents and square roots

m=(-1*-5±sqrt(25-4*4*-5))/(2*4)

Perform any multiplication or division, from left to right:

m=(-1*-5±sqrt(25-16*-5))/(2*4)

m=(-1*-5±sqrt(25--80))/(2*4)

Calculate any addition or subtraction, from left to right.

m=(-1*-5±sqrt(25+80))/(2*4)

m=(-1*-5±sqrt(105))/(2*4)

Perform any multiplication or division, from left to right:

m=(-1*-5±sqrt(105))/(8)

Perform any multiplication or division, from left to right:

m=(5±sqrt(105))/8

to get the result:

m=(5±sqrt(105))/8

3. Simplify square root (105)

Simplify 105 by finding its prime factors:

Tree view of the prime factors of <math>105</math>:

The prime factorization of 105 is 357

Write the prime factors:

105=3·5·7

3·5·7=105

4. Solve the equation for m

m=(5±sqrt(105))/8

The ± means two roots are possible.

Separate the equations:
m1=(5+sqrt(105))/8 and m2=(5-sqrt(105))/8

m1=(5+sqrt(105))/8

Remove the parentheses

m1=(5+sqrt(105))/8

m1=(5+10.247)/8

Calculate any addition or subtraction, from left to right.

m1=(5+10.247)/8

m1=(15.247)/8

Perform any multiplication or division, from left to right:

m1=15.2478

m1=1.906

m2=(5-sqrt(105))/8

m2=(5-10.247)/8

Calculate any addition or subtraction, from left to right.

m2=(5-10.247)/8

m2=(-5.247)/8

Perform any multiplication or division, from left to right:

m2=5.2478

m2=0.656

5. Find the intervals

To find the intervals of a quadratic inequality, we start by finding its parabola.

The roots of the parabola (where it meets the x-axis) are: -0.656, 1.906.

Since the a coefficient is positive (a=4), this is a "positive" quadratic inequality and the parabola points upward, like a smile!

If the inequality sign is ≤ or ≥ , then the intervals include the roots and we use a solid line. If the inequality sign is < or > the intervals do not include the roots and we use a dotted line.

6. Choose the correct interval (solution)

Since 4m25m5>0 has a > inequality sign, we look for the parabola intervals that are above the x-axis.

Solution:

Interval notation:

Why learn this

Whereas quadratic equations express the paths of arcs and the points along them, quadratic inequalities express the areas within and outside of these arcs and the ranges they cover. In other words, if quadratic equations tell us where the boundary is, then quadratic inequalities help us understand what we should focus on relative to that boundary. More practically, quadratic inequalities are used to create complex algorithms that fuel powerful software and to track how changes, such as prices at the grocery store, happen over time.

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