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Solution - Solving quadratic inequalities using the quadratic formula

Solution: 3x2
-3<=x<=-2
Interval notation: x[3,2]
x∈[-3,-2]

Step-by-step explanation

1. Simplify the expression

4 additional steps

3x2-5x>=4x2+6

Subtract 4x2 from both sides:

(3x2-5x)-4x2>=(4x2+6)-4x2

Group like terms:

(3x2-4x2)-5x>=(4x2+6)-4x2

Simplify the arithmetic:

-x2-5x>=(4x2+6)-4x2

Group like terms:

-x2-5x>=(4x2-4x2)+6

Simplify the arithmetic:

-x2-5x>=6

Simplify the quadratic inequality into its standard form

ax2+bx+c0

Subtract 6 from both sides of the inequality:

1x25x6

Subtract 6 from both sides:

1x25x666

Simplify the expression

1x25x60

2. Determine the quadratic inequality's coefficients a, b and c

The coefficients of our inequality, 1x25x60, are:

a = -1

b = -5

c = -6

3. Plug these coefficients into the quadratic formula

To find the roots of a quadratic equation, plug its coefficients (a, b and c ) into the quadratic formula:

x=(-b±sqrt(b2-4ac))/(2a)

a=1
b=5
c=6

x=(-1*-5±sqrt(-52-4*-1*-6))/(2*-1)

Simplify the exponents and square roots

x=(-1*-5±sqrt(25-4*-1*-6))/(2*-1)

Perform any multiplication or division, from left to right:

x=(-1*-5±sqrt(25--4*-6))/(2*-1)

x=(-1*-5±sqrt(25-24))/(2*-1)

Calculate any addition or subtraction, from left to right.

x=(-1*-5±sqrt(1))/(2*-1)

Perform any multiplication or division, from left to right:

x=(-1*-5±sqrt(1))/(-2)

Perform any multiplication or division, from left to right:

x=(5±sqrt(1))/(-2)

to get the result:

x=(5±sqrt(1))/(-2)

4. Simplify square root (1)

Simplify 1 by finding its prime factors:

The prime factorization of 1 is 1

Write the prime factors:

1=1

5. Solve the equation for x

x=(5±1)/(-2)

The ± means two roots are possible.

Separate the equations:
x1=(5+1)/(-2) and x2=(5-1)/(-2)

x1=(5+1)/(-2)

Calculate any addition or subtraction, from left to right.

x1=(5+1)/(-2)

x1=(6)/(-2)

Perform any multiplication or division, from left to right:

x1=62

x1=3

x2=(5-1)/(-2)

Calculate any addition or subtraction, from left to right.

x2=(5-1)/(-2)

x2=(4)/(-2)

Perform any multiplication or division, from left to right:

x2=42

x2=2

6. Find the intervals

To find the intervals of a quadratic inequality, we start by finding its parabola.

The roots of the parabola (where it meets the x-axis) are: -3, -2.

Since the a coefficient is negative (a=-1), this is a "negative" quadratic inequality and the parabola points downward, like a frown.

If the inequality sign is ≤ or ≥ , then the intervals include the roots and we use a solid line. If the inequality sign is < or > the intervals do not include the roots and we use a dotted line.

7. Choose the correct interval (solution)

Since 1x25x60 has a inequality sign, we look for the parabola intervals that are above the x-axis.

Solution:

Interval notation:

Why learn this

Whereas quadratic equations express the paths of arcs and the points along them, quadratic inequalities express the areas within and outside of these arcs and the ranges they cover. In other words, if quadratic equations tell us where the boundary is, then quadratic inequalities help us understand what we should focus on relative to that boundary. More practically, quadratic inequalities are used to create complex algorithms that fuel powerful software and to track how changes, such as prices at the grocery store, happen over time.

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