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Other Ways to Solve
Factoring binomials using the difference of squaresStep by Step Solution
Rearrange:
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
5*x^29*x-(-4)=0
Step 1 :
Equation at the end of step 1 :
(5x29 • x) - -4 = 0Step 2 :
Trying to factor as a Sum of Cubes :
2.1 Factoring: 5x30+4
Theory : A sum of two perfect cubes, a3 + b3 can be factored into :
(a+b) • (a2-ab+b2)
Proof : (a+b) • (a2-ab+b2) =
a3-a2b+ab2+ba2-b2a+b3 =
a3+(a2b-ba2)+(ab2-b2a)+b3=
a3+0+0+b3=
a3+b3
Check : 5 is not a cube !!
Ruling : Binomial can not be factored as the difference of two perfect cubes
Equation at the end of step 2 :
5x30 + 4 = 0
Step 3 :
Solving a Single Variable Equation :
3.1 Solve : 5x30+4 = 0
Subtract 4 from both sides of the equation :
5x30 = -4
Divide both sides of the equation by 5:
x30 = -4/5 = -0.800
x = 30th root of (-4/5)
The equation has no real solutions. It has 30 imaginary, or complex solutions.
These solutions are x = 30th root of -0.80000
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