Solution - Nonlinear equations

Step by step solution :

Step  1  :

Equation at the end of step  1  :

  (22n25 • n) -  636  = 0 
 Step  2  :
 Step  3  :

Pulling out like terms :

 3.1     Pull out like factors :

   4n²⁶ - 636  =   4 • (n²⁶ - 159) 

Trying to factor as a Difference of Squares :

 3.2      Factoring:  n²⁶ - 159 

Theory : A difference of two perfect squares,  A² - B²  can be factored into  (A+B) • (A-B)

Proof :  (A+B) • (A-B) =
         A² - AB + BA - B² =
         A² - AB + AB - B² =
         A² - B²

Note :  AB = BA is the commutative property of multiplication.

Note :  - AB + AB equals zero and is therefore eliminated from the expression.

Check : 159 is not a square !!

Ruling : Binomial can not be factored as the difference of two perfect squares.

Equation at the end of step  3  :

  4 • (n26 - 159)  = 0 

Step  4  :

Equations which are never true :

 4.1      Solve :    4   =  0

This equation has no solution.
A a non-zero constant never equals zero.

Solving a Single Variable Equation :

 4.2      Solve  :    n²⁶-159 = 0 

 Add  159  to both sides of the equation : 
                      n²⁶ = 159
                     n  =  26th root of (159) 

 The equation has two real solutions  
 These solutions are  n = ± 26th root of 159 = ± 1.2153  
 

Two solutions were found :