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Factoring binomials using the difference of squaresStep by Step Solution
Step 1 :
Step 2 :
Pulling out like terms :
2.1 Pull out like factors :
-x24 - 2 = -1 • (x24 + 2)
Trying to factor as a Sum of Cubes :
2.2 Factoring: x24 + 2
Theory : A sum of two perfect cubes, a3 + b3 can be factored into :
(a+b) • (a2-ab+b2)
Proof : (a+b) • (a2-ab+b2) =
a3-a2b+ab2+ba2-b2a+b3 =
a3+(a2b-ba2)+(ab2-b2a)+b3=
a3+0+0+b3=
a3+b3
Check : 2 is not a cube !!
Ruling : Binomial can not be factored as the difference of two perfect cubes
Equation at the end of step 2 :
-x24 - 2 = 0
Step 3 :
Solving a Single Variable Equation :
3.1 Solve : -x24-2 = 0
Add 2 to both sides of the equation :
-x24 = 2
Multiply both sides of the equation by (-1) : x24 = -2
x = 24th root of (-2)
The equation has no real solutions. It has 24 imaginary, or complex solutions.
These solutions are x = 24th root of -2.00000
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