Solution - Long multiplication
Step-by-step explanation
1. Rewrite the numbers from top to bottom aligned to the right
| Place value | ten thousands | thousands | hundreds | tens | ones |
| 7 | 1 | 8 | |||
| × | 1 | 0 | 5 | ||
2. Multiply the numbers using long multiplication method
Start by multiplying the ones digit (5) of the multiplier 105 by each digit of the multiplicand 718, from right to left.
Multiply the ones digit (5) of the multiplicator by the number in the ones place value:
5×8=40
Write 0 in the ones place.
Because the result is greater than 9, carry the 4 to the tens place.
| Place value | ten thousands | thousands | hundreds | tens | ones |
| 4 | |||||
| 7 | 1 | 8 | |||
| × | 1 | 0 | 5 | ||
| 0 | |||||
Multiply the ones digit (5) of the multiplicator by the number in the tens place value and add the carried number (4):
5×1+4=9
Write 9 in the tens place.
| Place value | ten thousands | thousands | hundreds | tens | ones |
| 4 | |||||
| 7 | 1 | 8 | |||
| × | 1 | 0 | 5 | ||
| 9 | 0 | ||||
Multiply the ones digit (5) of the multiplicator by the number in the hundreds place value:
5×7=35
Write 5 in the hundreds place.
Because the result is greater than 9, carry the 3 to the thousands place.
| Place value | ten thousands | thousands | hundreds | tens | ones |
| 3 | 4 | ||||
| 7 | 1 | 8 | |||
| × | 1 | 0 | 5 | ||
| 3 | 5 | 9 | 0 | ||
3,590 is the first partial product.
Because the tens digit of the multiplicator equals 0, skip to the next digit.
Proceed by multiplying the hundreds digit (1) of the multiplier (105) by each digit of the multiplicand (718), from right to left.
Because digit (1) is in hundreds place, we shift partial result by 2 place(s) by placing 2 zero(s).
| Place value | ten thousands | thousands | hundreds | tens | ones |
| 7 | 1 | 8 | |||
| × | 1 | 0 | 5 | ||
| 3 | 5 | 9 | 0 | ||
| 0 | 0 |
Multiply the hundreds digit (1) of the multiplicator by the number in the ones place value:
1×8=8
Write 8 in the hundreds place.
| Place value | ten thousands | thousands | hundreds | tens | ones |
| 7 | 1 | 8 | |||
| × | 1 | 0 | 5 | ||
| 3 | 5 | 9 | 0 | ||
| 8 | 0 | 0 |
Multiply the hundreds digit (1) of the multiplicator by the number in the tens place value:
1×1=1
Write 1 in the thousands place.
| Place value | ten thousands | thousands | hundreds | tens | ones |
| 7 | 1 | 8 | |||
| × | 1 | 0 | 5 | ||
| 3 | 5 | 9 | 0 | ||
| 1 | 8 | 0 | 0 |
Multiply the hundreds digit (1) of the multiplicator by the number in the hundreds place value:
1×7=7
Write 7 in the ten thousands place.
| Place value | ten thousands | thousands | hundreds | tens | ones |
| 7 | 1 | 8 | |||
| × | 1 | 0 | 5 | ||
| 3 | 5 | 9 | 0 | ||
| 7 | 1 | 8 | 0 | 0 |
71,800 is the second partial product.
3. Add the partial products
3590+71800=75390 long addition steps can be seen here
| Place value | ten thousands | thousands | hundreds | tens | ones |
| 7 | 1 | 8 | |||
| × | 1 | 0 | 5 | ||
| 3 | 5 | 9 | 0 | ||
| + | 7 | 1 | 8 | 0 | 0 |
| 7 | 5 | 3 | 9 | 0 |
The solution is: 75,390
How did we do?
Please leave us feedback.