Solution - Long multiplication

Start by multiplying the ones digit (5) of the multiplier 5 by each digit of the multiplicand 64, from right to left.

Multiply the ones digit (5) of the multiplicator by the number in the ones place value:
5×4=20

Write 0 in the ones place.

Because the result is greater than 9, carry the 2 to the tens place.

Multiply the ones digit (5) of the multiplicator by the number in the tens place value and add the carried number (2):
5×6+2=32

Write 2 in the tens place.

Because the result is greater than 9, carry the 3 to the hundreds place.

The solution is: 320