Solution - Long multiplication
315
Step-by-step explanation
1. Rewrite the numbers from top to bottom aligned to the right
Place value | hundreds | tens | ones |
6 | 3 | ||
× | 5 | ||
2. Multiply the numbers using long multiplication method
Start by multiplying the ones digit (5) of the multiplier 5 by each digit of the multiplicand 63, from right to left.
Multiply the ones digit (5) of the multiplicator by the number in the ones place value:
5×3=15
Write 5 in the ones place.
Because the result is greater than 9, carry the 1 to the tens place.
Place value | hundreds | tens | ones |
1 | |||
6 | 3 | ||
× | 5 | ||
5 |
Multiply the ones digit (5) of the multiplicator by the number in the tens place value and add the carried number (1):
5×6+1=31
Write 1 in the tens place.
Because the result is greater than 9, carry the 3 to the hundreds place.
Place value | hundreds | tens | ones |
3 | 1 | ||
6 | 3 | ||
× | 5 | ||
3 | 1 | 5 |
The solution is: 315
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