Solution - Long multiplication
Step-by-step explanation
1. Rewrite the numbers from top to bottom aligned to the right
| Place value | ten millions | millions | hundred thousands | ten thousands | thousands | hundreds | tens | ones |
| 6 | 2 | 5 | 0 | |||||
| × | 5 | 0 | 0 | 0 | ||||
2. Multiply the numbers using long multiplication method
Because the hundreds digit of the multiplicator equals 0, skip to the next digit.
Proceed by multiplying the thousands digit (5) of the multiplier (5,000) by each digit of the multiplicand (6,250), from right to left.
Because digit (5) is in thousands place, we shift partial result by 3 place(s) by placing 3 zero(s).
| Place value | ten millions | millions | hundred thousands | ten thousands | thousands | hundreds | tens | ones |
| 6 | 2 | 5 | 0 | |||||
| × | 5 | 0 | 0 | 0 | ||||
| 0 | 0 | 0 |
Multiply the thousands digit (5) of the multiplicator by the number in the ones place value:
5×0=0
Write 0 in the thousands place.
| Place value | ten millions | millions | hundred thousands | ten thousands | thousands | hundreds | tens | ones |
| 6 | 2 | 5 | 0 | |||||
| × | 5 | 0 | 0 | 0 | ||||
| 0 | 0 | 0 | 0 |
Multiply the thousands digit (5) of the multiplicator by the number in the tens place value:
5×5=25
Write 5 in the ten thousands place.
Because the result is greater than 9, carry the 2 to the hundred thousands place.
| Place value | ten millions | millions | hundred thousands | ten thousands | thousands | hundreds | tens | ones |
| 2 | ||||||||
| 6 | 2 | 5 | 0 | |||||
| × | 5 | 0 | 0 | 0 | ||||
| 5 | 0 | 0 | 0 | 0 |
Multiply the thousands digit (5) of the multiplicator by the number in the hundreds place value and add the carried number (2):
5×2+2=12
Write 2 in the hundred thousands place.
Because the result is greater than 9, carry the 1 to the millions place.
| Place value | ten millions | millions | hundred thousands | ten thousands | thousands | hundreds | tens | ones |
| 1 | 2 | |||||||
| 6 | 2 | 5 | 0 | |||||
| × | 5 | 0 | 0 | 0 | ||||
| 2 | 5 | 0 | 0 | 0 | 0 |
Multiply the thousands digit (5) of the multiplicator by the number in the thousands place value and add the carried number (1):
5×6+1=31
Write 1 in the millions place.
Because the result is greater than 9, carry the 3 to the ten millions place.
| Place value | ten millions | millions | hundred thousands | ten thousands | thousands | hundreds | tens | ones |
| 3 | 1 | 2 | ||||||
| 6 | 2 | 5 | 0 | |||||
| × | 5 | 0 | 0 | 0 | ||||
| 3 | 1 | 2 | 5 | 0 | 0 | 0 | 0 |
31,250,000 is the first partial product.
3. Add the partial products
31250000=31250000 long addition steps can be seen here
| Place value | ten millions | millions | hundred thousands | ten thousands | thousands | hundreds | tens | ones |
| 6 | 2 | 5 | 0 | |||||
| × | 5 | 0 | 0 | 0 | ||||
| + | 3 | 1 | 2 | 5 | 0 | 0 | 0 | 0 |
| 3 | 1 | 2 | 5 | 0 | 0 | 0 | 0 |
The solution is: 31,250,000
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