Solution - Long multiplication
Step-by-step explanation
1. Rewrite the numbers from top to bottom aligned to the right
| Place value | ones | . | tenths |
| 6 | . | 7 | |
| × | 2 | ||
Ignore the decimal points and multiply as if these are whole numbers (as if each most right digit is the ones digit):
In this case we removed 1 decimal place(s). So once calculated, the result will be reduced by the factor of 10.
| Place value | hundreds | tens | ones |
| 6 | 7 | ||
| × | 2 | ||
2. Multiply the numbers using long multiplication method
Start by multiplying the ones digit (2) of the multiplier 2 by each digit of the multiplicand 67, from right to left.
Multiply the ones digit (2) of the multiplicator by the number in the ones place value:
2×7=14
Write 4 in the ones place.
Because the result is greater than 9, carry the 1 to the tens place.
| Place value | hundreds | tens | ones |
| 1 | |||
| 6 | 7 | ||
| × | 2 | ||
| 4 |
Multiply the ones digit (2) of the multiplicator by the number in the tens place value and add the carried number (1):
2×6+1=13
Write 3 in the tens place.
Because the result is greater than 9, carry the 1 to the hundreds place.
| Place value | hundreds | tens | ones |
| 1 | 1 | ||
| 6 | 7 | ||
| × | 2 | ||
| 1 | 3 | 4 |
Because we have 1 digit(s) to the right of the decimal point in the numbers that are being multiplied, we move the decimal point 1 time(s) to the left (reducing the result by the factor of 10) to get the final result:
The solution is: 13.4
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