Solution - Long multiplication
477
Step-by-step explanation
1. Rewrite the numbers from top to bottom aligned to the right
| Place value | hundreds | tens | ones |
| 5 | 3 | ||
| × | 9 | ||
2. Multiply the numbers using long multiplication method
Start by multiplying the ones digit (9) of the multiplier 9 by each digit of the multiplicand 53, from right to left.
Multiply the ones digit (9) of the multiplicator by the number in the ones place value:
9×3=27
Write 7 in the ones place.
Because the result is greater than 9, carry the 2 to the tens place.
| Place value | hundreds | tens | ones |
| 2 | |||
| 5 | 3 | ||
| × | 9 | ||
| 7 |
Multiply the ones digit (9) of the multiplicator by the number in the tens place value and add the carried number (2):
9×5+2=47
Write 7 in the tens place.
Because the result is greater than 9, carry the 4 to the hundreds place.
| Place value | hundreds | tens | ones |
| 4 | 2 | ||
| 5 | 3 | ||
| × | 9 | ||
| 4 | 7 | 7 |
The solution is: 477
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