Solution - Long multiplication
Step-by-step explanation
1. Rewrite the numbers from top to bottom aligned to the right
| Place value | hundred thousands | ten thousands | thousands | hundreds | tens | ones |
| 5 | 0 | 1 | 0 | |||
| × | 7 | 2 | ||||
2. Multiply the numbers using long multiplication method
Start by multiplying the ones digit (2) of the multiplier 72 by each digit of the multiplicand 5,010, from right to left.
Multiply the ones digit (2) of the multiplicator by the number in the ones place value:
2×0=0
Write 0 in the ones place.
| Place value | hundred thousands | ten thousands | thousands | hundreds | tens | ones |
| 5 | 0 | 1 | 0 | |||
| × | 7 | 2 | ||||
| 0 | ||||||
Multiply the ones digit (2) of the multiplicator by the number in the tens place value:
2×1=2
Write 2 in the tens place.
| Place value | hundred thousands | ten thousands | thousands | hundreds | tens | ones |
| 5 | 0 | 1 | 0 | |||
| × | 7 | 2 | ||||
| 2 | 0 | |||||
Multiply the ones digit (2) of the multiplicator by the number in the hundreds place value:
2×0=0
Write 0 in the hundreds place.
| Place value | hundred thousands | ten thousands | thousands | hundreds | tens | ones |
| 5 | 0 | 1 | 0 | |||
| × | 7 | 2 | ||||
| 0 | 2 | 0 | ||||
Multiply the ones digit (2) of the multiplicator by the number in the thousands place value:
2×5=10
Write 0 in the thousands place.
Because the result is greater than 9, carry the 1 to the ten thousands place.
| Place value | hundred thousands | ten thousands | thousands | hundreds | tens | ones |
| 1 | ||||||
| 5 | 0 | 1 | 0 | |||
| × | 7 | 2 | ||||
| 1 | 0 | 0 | 2 | 0 | ||
10,020 is the first partial product.
Proceed by multiplying the tens digit (7) of the multiplier (72) by each digit of the multiplicand (5,010), from right to left.
Because digit (7) is in tens place, we shift partial result by 1 place(s) by placing 1 zero(s).
| Place value | hundred thousands | ten thousands | thousands | hundreds | tens | ones |
| 5 | 0 | 1 | 0 | |||
| × | 7 | 2 | ||||
| 1 | 0 | 0 | 2 | 0 | ||
| 0 |
Multiply the tens digit (7) of the multiplicator by the number in the ones place value:
7×0=0
Write 0 in the tens place.
| Place value | hundred thousands | ten thousands | thousands | hundreds | tens | ones |
| 5 | 0 | 1 | 0 | |||
| × | 7 | 2 | ||||
| 1 | 0 | 0 | 2 | 0 | ||
| 0 | 0 |
Multiply the tens digit (7) of the multiplicator by the number in the tens place value:
7×1=7
Write 7 in the hundreds place.
| Place value | hundred thousands | ten thousands | thousands | hundreds | tens | ones |
| 5 | 0 | 1 | 0 | |||
| × | 7 | 2 | ||||
| 1 | 0 | 0 | 2 | 0 | ||
| 7 | 0 | 0 |
Multiply the tens digit (7) of the multiplicator by the number in the hundreds place value:
7×0=0
Write 0 in the thousands place.
| Place value | hundred thousands | ten thousands | thousands | hundreds | tens | ones |
| 5 | 0 | 1 | 0 | |||
| × | 7 | 2 | ||||
| 1 | 0 | 0 | 2 | 0 | ||
| 0 | 7 | 0 | 0 |
Multiply the tens digit (7) of the multiplicator by the number in the thousands place value:
7×5=35
Write 5 in the ten thousands place.
Because the result is greater than 9, carry the 3 to the hundred thousands place.
| Place value | hundred thousands | ten thousands | thousands | hundreds | tens | ones |
| 3 | ||||||
| 5 | 0 | 1 | 0 | |||
| × | 7 | 2 | ||||
| 1 | 0 | 0 | 2 | 0 | ||
| 3 | 5 | 0 | 7 | 0 | 0 |
350,700 is the second partial product.
3. Add the partial products
10020+350700=360720 long addition steps can be seen here
| Place value | hundred thousands | ten thousands | thousands | hundreds | tens | ones |
| 5 | 0 | 1 | 0 | |||
| × | 7 | 2 | ||||
| 1 | 0 | 0 | 2 | 0 | ||
| + | 3 | 5 | 0 | 7 | 0 | 0 |
| 3 | 6 | 0 | 7 | 2 | 0 |
The solution is: 360,720
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