Solution - Long multiplication
Step-by-step explanation
1. Rewrite the numbers from top to bottom aligned to the right
| Place value | ones | . | tenths |
| 4 | . | 5 | |
| × | 7 | ||
Ignore the decimal points and multiply as if these are whole numbers (as if each most right digit is the ones digit):
In this case we removed 1 decimal place(s). So once calculated, the result will be reduced by the factor of 10.
| Place value | hundreds | tens | ones |
| 4 | 5 | ||
| × | 7 | ||
2. Multiply the numbers using long multiplication method
Start by multiplying the ones digit (7) of the multiplier 7 by each digit of the multiplicand 45, from right to left.
Multiply the ones digit (7) of the multiplicator by the number in the ones place value:
7×5=35
Write 5 in the ones place.
Because the result is greater than 9, carry the 3 to the tens place.
| Place value | hundreds | tens | ones |
| 3 | |||
| 4 | 5 | ||
| × | 7 | ||
| 5 |
Multiply the ones digit (7) of the multiplicator by the number in the tens place value and add the carried number (3):
7×4+3=31
Write 1 in the tens place.
Because the result is greater than 9, carry the 3 to the hundreds place.
| Place value | hundreds | tens | ones |
| 3 | 3 | ||
| 4 | 5 | ||
| × | 7 | ||
| 3 | 1 | 5 |
Because we have 1 digit(s) to the right of the decimal point in the numbers that are being multiplied, we move the decimal point 1 time(s) to the left (reducing the result by the factor of 10) to get the final result:
The solution is: 31.5
How did we do?
Please leave us feedback.