Solution - Long multiplication
117
Step-by-step explanation
1. Rewrite the numbers from top to bottom aligned to the right
| Place value | hundreds | tens | ones |
| 3 | 9 | ||
| × | 3 | ||
2. Multiply the numbers using long multiplication method
Start by multiplying the ones digit (3) of the multiplier 3 by each digit of the multiplicand 39, from right to left.
Multiply the ones digit (3) of the multiplicator by the number in the ones place value:
3×9=27
Write 7 in the ones place.
Because the result is greater than 9, carry the 2 to the tens place.
| Place value | hundreds | tens | ones |
| 2 | |||
| 3 | 9 | ||
| × | 3 | ||
| 7 |
Multiply the ones digit (3) of the multiplicator by the number in the tens place value and add the carried number (2):
3×3+2=11
Write 1 in the tens place.
Because the result is greater than 9, carry the 1 to the hundreds place.
| Place value | hundreds | tens | ones |
| 1 | 2 | ||
| 3 | 9 | ||
| × | 3 | ||
| 1 | 1 | 7 |
The solution is: 117
How did we do?
Please leave us feedback.