Solution - Long multiplication

Start by multiplying the ones digit (2) of the multiplier 2 by each digit of the multiplicand 35, from right to left.

Multiply the ones digit (2) of the multiplicator by the number in the ones place value:
2×5=10

Write 0 in the ones place.

Because the result is greater than 9, carry the 1 to the tens place.

Multiply the ones digit (2) of the multiplicator by the number in the tens place value and add the carried number (1):
2×3+1=7

Write 7 in the tens place.

The solution is: 70