Solution - Long multiplication
Step-by-step explanation
1. Rewrite the numbers from top to bottom aligned to the right
| Place value | hundreds | tens | ones | . | tenths | hundredths | thousandths | ten thousandths |
| 3 | 1 | 0 | ||||||
| × | 0 | . | 0 | 0 | 0 | 2 | ||
| . |
Ignore the decimal points and multiply as if these are whole numbers (as if each most right digit is the ones digit):
In this case we removed 4 decimal place(s). So once calculated, the result will be reduced by the factor of 10,000.
| Place value | hundreds | tens | ones |
| 3 | 1 | 0 | |
| × | 2 | ||
2. Multiply the numbers using long multiplication method
Start by multiplying the ones digit (2) of the multiplier 2 by each digit of the multiplicand 310, from right to left.
Multiply the ones digit (2) of the multiplicator by the number in the ones place value:
2×0=0
Write 0 in the ones place.
| Place value | hundreds | tens | ones |
| 3 | 1 | 0 | |
| × | 2 | ||
| 0 |
Multiply the ones digit (2) of the multiplicator by the number in the tens place value:
2×1=2
Write 2 in the tens place.
| Place value | hundreds | tens | ones |
| 3 | 1 | 0 | |
| × | 2 | ||
| 2 | 0 |
3. Add the partial products
Multiply the ones digit (2) of the multiplicator by the number in the hundreds place value:
2×3=6
Write 6 in the hundreds place.
| Place value | hundreds | tens | ones |
| 3 | 1 | 0 | |
| × | 2 | ||
| 6 | 2 | 0 |
Because we have 4 digit(s) to the right of the decimal point in the numbers that are being multiplied, we move the decimal point 4 time(s) to the left (reducing the result by the factor of 10,000) to get the final result:
The solution is: 0.062
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