Solution - Long multiplication
Step-by-step explanation
1. Rewrite the numbers from top to bottom aligned to the right
| Place value | ones | . | tenths | hundredths |
| 3 | . | 2 | 5 | |
| × | 4 | |||
Ignore the decimal points and multiply as if these are whole numbers (as if each most right digit is the ones digit):
In this case we removed 2 decimal place(s). So once calculated, the result will be reduced by the factor of 100.
| Place value | thousands | hundreds | tens | ones |
| 3 | 2 | 5 | ||
| × | 4 | |||
2. Multiply the numbers using long multiplication method
Start by multiplying the ones digit (4) of the multiplier 4 by each digit of the multiplicand 325, from right to left.
Multiply the ones digit (4) of the multiplicator by the number in the ones place value:
4×5=20
Write 0 in the ones place.
Because the result is greater than 9, carry the 2 to the tens place.
| Place value | thousands | hundreds | tens | ones |
| 2 | ||||
| 3 | 2 | 5 | ||
| × | 4 | |||
| 0 |
Multiply the ones digit (4) of the multiplicator by the number in the tens place value and add the carried number (2):
4×2+2=10
Write 0 in the tens place.
Because the result is greater than 9, carry the 1 to the hundreds place.
| Place value | thousands | hundreds | tens | ones |
| 1 | 2 | |||
| 3 | 2 | 5 | ||
| × | 4 | |||
| 0 | 0 |
Multiply the ones digit (4) of the multiplicator by the number in the hundreds place value and add the carried number (1):
4×3+1=13
Write 3 in the hundreds place.
Because the result is greater than 9, carry the 1 to the thousands place.
| Place value | thousands | hundreds | tens | ones |
| 1 | 1 | 2 | ||
| 3 | 2 | 5 | ||
| × | 4 | |||
| 1 | 3 | 0 | 0 |
Because we have 2 digit(s) to the right of the decimal point in the numbers that are being multiplied, we move the decimal point 2 time(s) to the left (reducing the result by the factor of 100) to get the final result:
The solution is: 13
How did we do?
Please leave us feedback.