Solution - Long multiplication

Start by multiplying the ones digit (3) of the multiplier 3 by each digit of the multiplicand 29, from right to left.

Multiply the ones digit (3) of the multiplicator by the number in the ones place value:
3×9=27

Write 7 in the ones place.

Because the result is greater than 9, carry the 2 to the tens place.

Multiply the ones digit (3) of the multiplicator by the number in the tens place value and add the carried number (2):
3×2+2=8

Write 8 in the tens place.

The solution is: 87