Solution - Long multiplication
Step-by-step explanation
1. Rewrite the numbers from top to bottom aligned to the right
| Place value | thousands | hundreds | tens | ones |
| 2 | 7 | |||
| × | 3 | 0 | 0 | |
2. Multiply the numbers using long multiplication method
Because the tens digit of the multiplicator equals 0, skip to the next digit.
Proceed by multiplying the hundreds digit (3) of the multiplier (300) by each digit of the multiplicand (27), from right to left.
Because digit (3) is in hundreds place, we shift partial result by 2 place(s) by placing 2 zero(s).
| Place value | thousands | hundreds | tens | ones |
| 2 | 7 | |||
| × | 3 | 0 | 0 | |
| 0 | 0 |
Multiply the hundreds digit (3) of the multiplicator by the number in the ones place value:
3×7=21
Write 1 in the hundreds place.
Because the result is greater than 9, carry the 2 to the thousands place.
| Place value | thousands | hundreds | tens | ones |
| 2 | ||||
| 2 | 7 | |||
| × | 3 | 0 | 0 | |
| 1 | 0 | 0 |
Multiply the hundreds digit (3) of the multiplicator by the number in the tens place value and add the carried number (2):
3×2+2=8
Write 8 in the thousands place.
| Place value | thousands | hundreds | tens | ones |
| 2 | ||||
| 2 | 7 | |||
| × | 3 | 0 | 0 | |
| 8 | 1 | 0 | 0 |
8,100 is the first partial product.
3. Add the partial products
8100=8100 long addition steps can be seen here
| Place value | thousands | hundreds | tens | ones |
| 2 | 7 | |||
| × | 3 | 0 | 0 | |
| + | 8 | 1 | 0 | 0 |
| 8 | 1 | 0 | 0 |
The solution is: 8,100
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