Solution - Long multiplication

Start by multiplying the ones digit (9) of the multiplier 4,019 by each digit of the multiplicand 2,259, from right to left.

Multiply the ones digit (9) of the multiplicator by the number in the ones place value:
9×9=81

Write 1 in the ones place.

Because the result is greater than 9, carry the 8 to the tens place.

Multiply the ones digit (9) of the multiplicator by the number in the tens place value and add the carried number (8):
9×5+8=53

Write 3 in the tens place.

Because the result is greater than 9, carry the 5 to the hundreds place.

Multiply the ones digit (9) of the multiplicator by the number in the hundreds place value and add the carried number (5):
9×2+5=23

Write 3 in the hundreds place.

Because the result is greater than 9, carry the 2 to the thousands place.

Multiply the ones digit (9) of the multiplicator by the number in the thousands place value and add the carried number (2):
9×2+2=20

Write 0 in the thousands place.

Because the result is greater than 9, carry the 2 to the ten thousands place.

20,331 is the first partial product.

Proceed by multiplying the tens digit (1) of the multiplier (4,019) by each digit of the multiplicand (2,259), from right to left.

Because digit (1) is in tens place, we shift partial result by 1 place(s) by placing 1 zero(s).

Multiply the tens digit (1) of the multiplicator by the number in the ones place value:
1×9=9

Write 9 in the tens place.

Multiply the tens digit (1) of the multiplicator by the number in the tens place value:
1×5=5

Write 5 in the hundreds place.

Multiply the tens digit (1) of the multiplicator by the number in the hundreds place value:
1×2=2

Write 2 in the thousands place.

Multiply the tens digit (1) of the multiplicator by the number in the thousands place value:
1×2=2

Write 2 in the ten thousands place.

22,590 is the second partial product.

Because the hundreds digit of the multiplicator equals 0, skip to the next digit.

Proceed by multiplying the thousands digit (4) of the multiplier (4,019) by each digit of the multiplicand (2,259), from right to left.

Because digit (4) is in thousands place, we shift partial result by 3 place(s) by placing 3 zero(s).

Multiply the thousands digit (4) of the multiplicator by the number in the ones place value:
4×9=36

Write 6 in the thousands place.

Because the result is greater than 9, carry the 3 to the ten thousands place.

Multiply the thousands digit (4) of the multiplicator by the number in the tens place value and add the carried number (3):
4×5+3=23

Write 3 in the ten thousands place.

Because the result is greater than 9, carry the 2 to the hundred thousands place.

Multiply the thousands digit (4) of the multiplicator by the number in the hundreds place value and add the carried number (2):
4×2+2=10

Write 0 in the hundred thousands place.

Because the result is greater than 9, carry the 1 to the millions place.

Multiply the thousands digit (4) of the multiplicator by the number in the thousands place value and add the carried number (1):
4×2+1=9

Write 9 in the millions place.

9,036,000 is the third partial product.

20331+22590+9036000=9078921 long addition steps can be seen here

Because we have 4 digit(s) to the right of the decimal point in the numbers that are being multiplied, we move the decimal point 4 time(s) to the left (reducing the result by the factor of 10,000) to get the final result:

The solution is: 907.8921