Solution - Long multiplication

Start by multiplying the ones digit (3) of the multiplier 3 by each digit of the multiplicand 2,187, from right to left.

Multiply the ones digit (3) of the multiplicator by the number in the ones place value:
3×7=21

Write 1 in the ones place.

Because the result is greater than 9, carry the 2 to the tens place.

Multiply the ones digit (3) of the multiplicator by the number in the tens place value and add the carried number (2):
3×8+2=26

Write 6 in the tens place.

Because the result is greater than 9, carry the 2 to the hundreds place.

Multiply the ones digit (3) of the multiplicator by the number in the hundreds place value and add the carried number (2):
3×1+2=5

Write 5 in the hundreds place.

Multiply the ones digit (3) of the multiplicator by the number in the thousands place value:
3×2=6

Write 6 in the thousands place.

The solution is: 6,561