Solution - Long multiplication
Step-by-step explanation
1. Rewrite the numbers from top to bottom aligned to the right
| Place value | ones | . | tenths | hundredths |
| 2 | . | 7 | ||
| × | 0 | . | 0 | 3 |
| . |
Ignore the decimal points and multiply as if these are whole numbers (as if each most right digit is the ones digit):
In this case we removed 3 decimal place(s). So once calculated, the result will be reduced by the factor of 1,000.
| Place value | tens | ones |
| 2 | 7 | |
| × | 3 | |
2. Multiply the numbers using long multiplication method
Start by multiplying the ones digit (3) of the multiplier 3 by each digit of the multiplicand 27, from right to left.
Multiply the ones digit (3) of the multiplicator by the number in the ones place value:
3×7=21
Write 1 in the ones place.
Because the result is greater than 9, carry the 2 to the tens place.
| Place value | tens | ones |
| 2 | ||
| 2 | 7 | |
| × | 3 | |
| 1 |
3. Add the partial products
Multiply the ones digit (3) of the multiplicator by the number in the tens place value and add the carried number (2):
3×2+2=8
Write 8 in the tens place.
| Place value | tens | ones |
| 2 | ||
| 2 | 7 | |
| × | 3 | |
| 8 | 1 |
Because we have 3 digit(s) to the right of the decimal point in the numbers that are being multiplied, we move the decimal point 3 time(s) to the left (reducing the result by the factor of 1,000) to get the final result:
The solution is: 0.081
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