Solution - Long multiplication
Step-by-step explanation
1. Rewrite the numbers from top to bottom aligned to the right
| Place value | ones | . | tenths | hundredths |
| 2 | . | 4 | 3 | |
| × | 2 | |||
Ignore the decimal points and multiply as if these are whole numbers (as if each most right digit is the ones digit):
In this case we removed 2 decimal place(s). So once calculated, the result will be reduced by the factor of 100.
| Place value | hundreds | tens | ones |
| 2 | 4 | 3 | |
| × | 2 | ||
2. Multiply the numbers using long multiplication method
Start by multiplying the ones digit (2) of the multiplier 2 by each digit of the multiplicand 243, from right to left.
Multiply the ones digit (2) of the multiplicator by the number in the ones place value:
2×3=6
Write 6 in the ones place.
| Place value | hundreds | tens | ones |
| 2 | 4 | 3 | |
| × | 2 | ||
| 6 |
Multiply the ones digit (2) of the multiplicator by the number in the tens place value:
2×4=8
Write 8 in the tens place.
| Place value | hundreds | tens | ones |
| 2 | 4 | 3 | |
| × | 2 | ||
| 8 | 6 |
Multiply the ones digit (2) of the multiplicator by the number in the hundreds place value:
2×2=4
Write 4 in the hundreds place.
| Place value | hundreds | tens | ones |
| 2 | 4 | 3 | |
| × | 2 | ||
| 4 | 8 | 6 |
Because we have 2 digit(s) to the right of the decimal point in the numbers that are being multiplied, we move the decimal point 2 time(s) to the left (reducing the result by the factor of 100) to get the final result:
The solution is: 4.86
How did we do?
Please leave us feedback.