Solution - Long multiplication
Step-by-step explanation
1. Rewrite the numbers from top to bottom aligned to the right
| Place value | hundred thousands | ten thousands | thousands | hundreds | tens | ones |
| 1 | 8 | 2 | ||||
| × | 1 | 0 | 0 | 1 | ||
2. Multiply the numbers using long multiplication method
Start by multiplying the ones digit (1) of the multiplier 1,001 by each digit of the multiplicand 182, from right to left.
Multiply the ones digit (1) of the multiplicator by the number in the ones place value:
1×2=2
Write 2 in the ones place.
| Place value | hundred thousands | ten thousands | thousands | hundreds | tens | ones |
| 1 | 8 | 2 | ||||
| × | 1 | 0 | 0 | 1 | ||
| 2 | ||||||
Multiply the ones digit (1) of the multiplicator by the number in the tens place value:
1×8=8
Write 8 in the tens place.
| Place value | hundred thousands | ten thousands | thousands | hundreds | tens | ones |
| 1 | 8 | 2 | ||||
| × | 1 | 0 | 0 | 1 | ||
| 8 | 2 | |||||
Multiply the ones digit (1) of the multiplicator by the number in the hundreds place value:
1×1=1
Write 1 in the hundreds place.
| Place value | hundred thousands | ten thousands | thousands | hundreds | tens | ones |
| 1 | 8 | 2 | ||||
| × | 1 | 0 | 0 | 1 | ||
| 1 | 8 | 2 | ||||
182 is the first partial product.
Because the hundreds digit of the multiplicator equals 0, skip to the next digit.
Proceed by multiplying the thousands digit (1) of the multiplier (1,001) by each digit of the multiplicand (182), from right to left.
Because digit (1) is in thousands place, we shift partial result by 3 place(s) by placing 3 zero(s).
| Place value | hundred thousands | ten thousands | thousands | hundreds | tens | ones |
| 1 | 8 | 2 | ||||
| × | 1 | 0 | 0 | 1 | ||
| 1 | 8 | 2 | ||||
| 0 | 0 | 0 |
Multiply the thousands digit (1) of the multiplicator by the number in the ones place value:
1×2=2
Write 2 in the thousands place.
| Place value | hundred thousands | ten thousands | thousands | hundreds | tens | ones |
| 1 | 8 | 2 | ||||
| × | 1 | 0 | 0 | 1 | ||
| 1 | 8 | 2 | ||||
| 2 | 0 | 0 | 0 |
Multiply the thousands digit (1) of the multiplicator by the number in the tens place value:
1×8=8
Write 8 in the ten thousands place.
| Place value | hundred thousands | ten thousands | thousands | hundreds | tens | ones |
| 1 | 8 | 2 | ||||
| × | 1 | 0 | 0 | 1 | ||
| 1 | 8 | 2 | ||||
| 8 | 2 | 0 | 0 | 0 |
Multiply the thousands digit (1) of the multiplicator by the number in the hundreds place value:
1×1=1
Write 1 in the hundred thousands place.
| Place value | hundred thousands | ten thousands | thousands | hundreds | tens | ones |
| 1 | 8 | 2 | ||||
| × | 1 | 0 | 0 | 1 | ||
| 1 | 8 | 2 | ||||
| 1 | 8 | 2 | 0 | 0 | 0 |
182,000 is the second partial product.
3. Add the partial products
182+182000=182182 long addition steps can be seen here
| Place value | hundred thousands | ten thousands | thousands | hundreds | tens | ones |
| 1 | 8 | 2 | ||||
| × | 1 | 0 | 0 | 1 | ||
| 1 | 8 | 2 | ||||
| + | 1 | 8 | 2 | 0 | 0 | 0 |
| 1 | 8 | 2 | 1 | 8 | 2 |
The solution is: 182,182
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