Solution - Long multiplication

Start by multiplying the ones digit (2) of the multiplier 2 by each digit of the multiplicand 180, from right to left.

Multiply the ones digit (2) of the multiplicator by the number in the ones place value:
2×0=0

Write 0 in the ones place.

Multiply the ones digit (2) of the multiplicator by the number in the tens place value:
2×8=16

Write 6 in the tens place.

Because the result is greater than 9, carry the 1 to the hundreds place.

Multiply the ones digit (2) of the multiplicator by the number in the hundreds place value and add the carried number (1):
2×1+1=3

Write 3 in the hundreds place.

The solution is: 360